AP EAPCET 24-Aug-2021 Shift 1 Paper

Equation of line passing through the point P(1,2) which makes an angle 45° with the X-axis is (y−2)=m(x−1) and m=tan‌θ
=tan‌45°=1
∴ Equation is y−2=1(x−1)
y−2=x−1
⇒x−y+1=0
Point of intersection of lines x−y+1=0 and
3x+4y+5=0 is Q
Then, for Q
x−y+1=0,y=x+1
Pult it in 3x+4v+5=0
3x+4(x+1)+5=0
⇒3x+4x+4+5=0
⇒7x+9=0
x=−

9

7

,y=−

9

7

+1=−

2

7

∴ Q is (−

9

7

,−

2

7

)
PQ=√(x2−x1)2+(y2−y1)2 [distance formula] =√2(

16

7

)2=

16

7

√2