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Question : 31 of 160
Marks:
+1,
-0
Solution:
Given,
(a×b)×c=|b||c|a ⇒−{c×(a×b)}=|b||c|a [∵a×b=−b×a] ⇒−{(c.b)a−(c.a)b}=|b||c|a ⇒−(b.c)a+(c.a)b=|b||c|a By comparing
−b.c=|b||c| and
ca=0 −|b||c|cos‌θ=|b||c| cos‌θ=− sin‌θ=√1−cos2θ =√1− sin‌θ=
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