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Question : 19 of 160
Marks:
+1,
-0
Solution:
For improper fraction
[] (i)
P(x) and
q(x) both are polynomial.
(ii) Degree of
p(x)≥ degrec of
q(x).
Option (a) = Degree of
p(x)=2 Degree of
q(x)=mathbf‌4 It is not improper fraction.
Option (b) = Degree of
p(x)=2 Degree of
q(x)=3 2 < 3
∴ It is not improper fraction.
Option (c) = Degree of
p(x)=1 Degree of
q(x)=2 1<2 ∴ It is not improper fraction.
Option (d) = Degrec of
p(x)=2= degree of
q(x) ∴ It is improper fraction.
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