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Question : 129 of 160
Marks:
+1,
-0
Solution:
Molecular orbital configuration of
O2=σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π*2px1π*2py1
⇒ Paramagnetic
Bond order
==2 O2+=σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2px1
⇒ Paramagnetic
Bond order
==2.5 C2=σ1s2σ21s2σ2s2σ*2s2π2px2π2py2 ⇒ Diamagnetic
Bond order
==2 C2+=σls2σ*1s2σ2s2σ+2s2π2px2π2py1 ⇒ Paramagnetic
NO=σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2π*2px1 ⇒ Paramagnetic
Bond order
==2.5 NO+=σ1s2σ*1s2σ2s2σ*2s2σ2pz2π2px2π2py2
⇒ Diamagnetic
Bond order
==3 N2=σ1s2σ*1s2σ2s2σ*2s2σ2px2π2py2π2pz2 ⇒ Paramagnetic
Bond order
==3 N2+=σ1s2σ*1s2σ2s2σ*2s2σ2px2π2py2σ2pz1 ⇒ Paramagnetic
Bond order
==2.5 Bond order increase from
NO to
NO+.
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