AP EAPCET 24-Aug-2021 Shift 1 Paper

Given that, emf of batrery, E=6V
Resistance, R=12ΩInductance, L=2H
We know that, the instantaneous current in the circuit containing R and L in series with battery of emf E is
I=I0(1−e

−z

2

t)
where, maximum current at steady state I0=

E

R

∴ I=

E

R

(1−e

−R

t

)
Now, the rate of increase of current.

dI

dt

=

E

R

[0−(

−R

L

)e

−R

2

t]=

E

L

e

−R

L

t
At (t=0) initial condition,

dl

dt

|t=0=

E

L

e0=

E

L

=

6

2

=3A∕s