AP EAPCET 24-Aug-2021 Shift 1 Paper

Given that, electric current, I=9A
Let n be the number of electron passing through a conductor in time t.
We know that, I=

q

t

and q=ne
∴ I=

ne

t

⇒

n

t

=

1

e

Substituting the values, we get
Number of electron flowing per second.

n

t

=

9

1.6×10−19

=5.6×1019 electrons per second