AP EAPCET 24-Aug-2021 Shift 1 Paper

Given that, capacitance of capacitor.
C=0.75µF
Voltage applied, V=20V
Using an expression of charge stored on each plate of capacitor, Q=CV
Substituting the values, we get
Q=0.75×10−6×20=15×10−6C
Q=15µC
Hence, 15µC of charge stored on each plate of capacitor.