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Question : 75 of 160
Marks:
+1,
-0
Solution:
‌∫‌‌‌‌dx‌=∫‌‌‌‌dx‌∫‌‌‌√‌−1.dx‌‌ Put ‌‌−1=t⇒‌‌dx=−dt‌‌ at ‌x=‌⇒t=4‌ and at ‌x=‌⇒t=1‌=−t‌⋅dt=√t⋅dt‌=[‌]14=‌[t‌]14‌=‌[4‌−1‌]=‌(8−1)‌=‌
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