\int { {\dx}}/{( {\x}+1) \sqrt{ {\x}^2+1}}= [AP EAPCET 23 May 2025 S2]

Correct Answer is : −1√2Sinh−1(1−x1+x)+c

{1}/{\sqrt{2}} {\Sinh}^{-1} (\frac{1+x}{1-x}) +c

{1}/{\sqrt{2}} {\Sinh}^{-1} (\frac{1-x}{1+x}) +c

- {1}/{\sqrt{2}} {\Sinh}^{-1} (\frac{1-x}{1+x}) +c

- {1}/{\sqrt{2}} {\Sinh}^{-1} (\frac{1+x}{1-x}) +c

AP EAPCET 23 May 2025 Shift 2 Paper

Section: Mathematics

Question : 71 of 160

Marks: +1, -0

∫‌

(x+1)√x2+1

[AP EAPCET 23 May 2025 S2]

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