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Question : 9 of 160
Marks:
+1,
-0
Solution:
‌(1+√3i)6−(√3+i)6‌=26⋅(‌+‌i)6−(‌+‌i)626‌=26[(cos‌+sin‌‌i)6−(cos‌+sin‌‌i)](Using De-Moivre's theorem)
‌=26[(cos‌2‌π+sin‌2πi)−(cos‌π+sin‌πi)]‌=64[(1+0)−(−1+0)]‌=64(1+1)=128
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