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Question : 76 of 160
Marks:
+1,
-0
Solution:
‌‌ Let ‌I=∫‌‌cos4x‌dx‌=∫‌‌‌‌dx=∫‌‌ sec4x‌dx‌=∫‌‌ sec2x(1+tan2x)‌dx=∫‌√3(1+u2)du where
u=tan‌x‌=(u+‌)‌√3‌=(√3+‌)−(‌+‌)‌=‌−(‌+‌)‌=‌−(‌)=2√3−‌‌=‌=‌=‌
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