AP EAPCET 23 May 2025 Shift 1 Paper

In a closed organ pipe, the number of nodes formed in the nth harmonic is equal to (‌

n+1

2

) if n is odd.
Thus, for the fifth (n=5) harmonic, the number of nodes =‌

5+1

2

=3 and for the ninth harmonic ( n=9 ), the number of nodes =‌

9+1

2

=5