If rotational inertia parameter of a body rolling down a rough inclined plane (of inclination \\theta and height h ) without slipping is given by \\beta=\I_{\CM} / \MR^{2}, then time taken by the body to reach the bottom of the inclined plane is given by ______

Correct Answer is : t=1sinθ√(1+β)2hg

t=\frac{1}{\sin \\theta} \\sqrt{\frac{(1+\\beta) 2 h}{g}}

t=\frac{1}{\cos\\theta} \\sqrt{\frac{(1+\\beta) 2 h}{g}}

t=\frac{1}{\sin \\theta} \\sqrt{\frac{(1-\\beta) 2 h}{g}}

t=\frac{1}{\sin \\theta} \\sqrt{\frac{(1+\\beta) h}{g}}

AP EAPCET 23-Aug-2021 Shift 2 Paper

Section: Physics

Question : 92 of 160

Marks: +1, -0

If rotational inertia parameter of a body rolling down a rough inclined plane (of inclination θ and height h ) without slipping is given by β=

ICM

MR2

, then time taken by the body to reach the bottom of the inclined plane is given by ______

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