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Question : 74 of 160
Marks:
+1,
-0
Solution:
Let
I=∫(1−cos‌x)cosec2xdx I=∫cosec2xdx−∫cos‌x.cosec2xdx =−cot‌x−∫cos‌x.cosec‌x‌d‌x =−cot‌x+cosec‌x+C =+C [∵1−cos‌x=2sin2] =+C I=tan()+C
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