AP EAPCET 23-Aug-2021 Shift 2 Paper

Given lines, l1:x=0
l2:y=0
l3:3x+4y−12=0
⇒y=

−3

4

x+3
∵ Circle touches X-axis and Y-axis.
⇒ Then, perpendicular distance from X-axis and Y-axis to center is same and let's say it r.
∴ Center =(r,r)
Let circle touches l3 at P.
∴OP=r
|

3r+4r−12

√32+42

|=r
⇒±r=

7r−12

5

When r=

7r−12

5

⇒2r=12
⇒r=6
and when −r=

7r−12

5

⇒12r=12
r=1