AP EAPCET 23-Aug-2021 Shift 2 Paper

Let m1 be the slope of the line, which passes through the point (3,2) and m2 be the slope of x−2y=3
∴m2=

− Coefficient of x

Coefficient of y

=

−1

−2

=

1

2

Given that, the angle between lines is 45°
∴tan‌45°=|

m1−m2

1+m1m2

|
1=±|

m1− 1 2

1+m1( 1 2 )

|
When, 1=+(

2m1−1

2+m1

)
⇒2+m1=2m1−1
⇒m1=3
and when 1=−(

2m1−1

2+m1

)
⇒m1=

−1

3

Hence, equation a line passing through (3,2) and having slope 3 is
y−2=3(x−3)
⇒y−2=3x−9
⇒3x−y=7
When slope is

−1

3

Then the, equation is y−2=

−1

3

(x−3)
3y−6=−x+3
⇒x+3y=9