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Question : 28 of 160
Marks:
+1,
-0
Solution:
Let
OA=+− ,
OB=2+3 ,
OC=5−2 ,
OD=− ∴AB=OB−OA =+2+ ⇒|AB|=√12+22+12=√6 BC=OC−OB =−2+2−2 ⇒|BC|=√(−2)2+22+(−2)2=2√3 CD=OD−OC =−6+3 ⇒|CD|=3√5 DA=OA−OD =+2−2 ⇒|DA|=3∵ All the sides has different length and no two sides are equal and parallel.
Hence, it forms only quadrilateral.
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