AP EAPCET 23-Aug-2021 Shift 1 Paper

Given, height through which body slides =H
Radius of circular loop =R
Force on body A,FA=√2 weight (w)Let, velocity of body at A=vA
Acceleration due lo gravity =g

mvA2

R

=√2w=√2‌mg ⇒vA2=√2Rg
By using law of conservation of energy
Energy at position (P)= Energy at position (A)
mgH=

1

2

mvA2+mgR
⇒2gH=vA2+2gR =√2gR+2gR=(√2+2)gR
⇒H=(

1

√2

+1)R=1.7R =1.5R=

3

2

R