Let \ABCDEF be a regular hexagon with the vertices \A, \B, \C, \D, \E, \F counter clockwise. Then the vector \overrightarrow{\AB}+\overrightarrow{\BC} is equal parallel to

Correct Answer is : →FE+→ED

\overrightarrow{\BC}+\overrightarrow{\CD}

\overrightarrow{ \CD}+\overrightarrow{ \DE}

\overrightarrow{\AF}+\overrightarrow{\FE}

\overrightarrow{\FE}+\overrightarrow{\ED}

AP EAPCET 23-Aug-2021 Shift 1 Paper

Section: Mathematics

Question : 29 of 160

Marks: +1, -0

Let ABCDEF be a regular hexagon with the vertices A,B,C,D,E,F counter clockwise. Then the vector

→

is equal parallel to

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