+... and parallel equivalent capacitance. Ceq=Cd+Cb+Cc+... Now, since C4 and C5 are in parallel. So, their equivalent capacitance, ∴Ca=2+1=3µF Now Ca,C3 and C6 are in series will give equivalent capacitance, ∴
1
Cb
=
1
Cd
+
1
C3
+
1
C6
=
1
3
+
1
3
+
1
3
=
3
3
=1 ⇒Cb=1µF Again Cc and Ca in parallel will give, Cc=Cb+C8=1+2=3µF Again C6,C2 and C7 are in series will give, ∴
1
Cd
=
1
C2
+
1
C7
+
1
Cc
=
1
3
+
1
3
+
1
3
=
3
3
⇒Cd=1µF Again Cd is in parallel with Cg, and give,Cf=Cd+C9=1+2=3µF and finally Cf is in series with C1 and C10 and give