AP EAPCET 23-Aug-2021 Shift 1 Paper

Given, ratio of fundamental frequencies be f1:f2:f3=1:2:3
Let ratio of length be l1:l2:l3.
Since, f=

1

2l

√

T

µ

where, f is frequency,
l is length of string,
T is tension
and µ is mass per unit length.
∴l∝

1

f

So, l1:l2:l3=

1

f1

:

1

f2

:

1

f3

=

1

1

:

1

2

:

1

3

=

6

6

:

3

6

:

2

6

=6:3:2