\int_{0}^{\pi \/ 4} \frac{\cos ^2 x}{\cos ^2 x+4 \sin ^2 x} \dx= [AP EAPCET 22 May 2025 S2]

Correct Answer is : −π12+23Tan−12

\frac{\pi}{2}-\frac{1}{3} {\Tan}^{-1} 2

-\frac{\pi}{4}-\frac{4}{3} {\Tan}^{-1} 2

\frac{\pi}{6}+\frac{2}{3} {\Tan}^{-1} 2

-\frac{\pi}{12}+\frac{2}{3} {\Tan}^{-1} 2

AP EAPCET 22 May 2025 Shift 2 Paper

Section: Mathematics

Question : 76 of 160

Marks: +1, -0

π∕4

∫

‌

cos2x

cos2x+4sin‌2x

‌dx=

[AP EAPCET 22 May 2025 S2]

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