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Question : 59 of 160
Marks:
+1,
-0
Solution:
Evaluate
[x] as
x⟶0−As
x approaches 0 from the left
[x]=−1{x} as
x⟶0−‌{x}=x−[x]=x−(−1)=x+1‌‌ as ‌x⟶0−,{x}⟶1‌‌‌‌=‌| sin‌−1(x−1) |
| 2−(x+1) |
‌=‌as
x⟶0−, the limit becomes
‌=−‌=−‌Therefore,
θ=−‌sin‌θ+cos‌θ‌=sin‌(−‌)+cos(−‌)‌=−1sin‌θ+cos‌θ‌=−1
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