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Question : 74 of 160
Marks:
+1,
-0
Solution:
I=∫‌‌|tan(x−‌)|‌dxPut
tan(x−‌)=0⇒x−‌=0I‌=∫‌‌−tan(x−‌)‌dx+∫‌‌tan(x−‌)‌dx‌=−[log( sec(x−‌)]−π‌+[log‌ ‌s‌e‌c(x−‌)]‌‌.‌⇒log( sec(‌))+log( sec(‌))‌=log( sec(‌) sec(‌))‌=log(2√2‌)
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