AP EAPCET 22 May 2024 Shift 2 Solved Paper

Section: Mathematics

© examsiri.com

Question : 69 of 160

Marks: +1, -0

∫e4x2+8x−4(x+1)‌cos(3x2+6x−4)‌dx=

[AP EAPCET 22 May 2024 Shift 2]

‌
e4x2+8x−4
25
[3‌sin‌(3x2+6x−4)−4‌cos(3x2+6x−4)]+c
‌
e4x2+8x−4
50
[4‌cos(3x2+6x−4)+3‌sin‌(3x2+6x−4)]+c
‌
e4x2+8x−4
25
[3‌cos(3x2+6x−4)+4‌sin‌(3x2+6x−4)]+c
‌
e4x2+8x−4
50
[4‌sin‌(3x2+6x−4)−3‌cos(3x2+6x−4)]+c

Go to Question:

Prev Question

Next Question