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Question : 74 of 160
Marks:
+1,
-0
Solution:
‌ln(tan‌x+cot‌x)‌dx=ln(‌)‌dx‌=(ln‌2−ln‌s‌i‌n‌2x)‌dx‌=ln‌2‌dx−ln‌s‌i‌n‌2x‌dx‌‌ put ‌2x=t,dx=‌‌=‌‌ln‌2−‌‌ln‌s‌i‌n‌t‌dt‌=‌‌ln‌2−ln‌s‌i‌n‌t‌dt‌=‌‌ln‌2−(−‌‌ln‌2)‌[∵ln‌s‌i‌n‌x=−‌‌ln‌2]‌=π‌ln‌2
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