If A=\left[\begin{array}{ccc}1 & 2 & -2 \ 2 & -1 & 2 \ -1 & 1 & -2]\end{array}, then A+2 A^{-1}= [AP EAPCET 21 May 2025 S2]

Correct Answer is : [1404−5−40−2−7]

{\left[\begin{array}{ccc}1 & 4 & 0 \ 4 & -5 & -4 \ 0 & -2 & -7]\end{array}}

{\left[\begin{array}{ccc}0 & 2 & 2 \ 2 & -4 & -6 \ 2 & -3 & -5]\end{array}}

{\left[\begin{array}{ccc}0 & 2 & 1 \ 2 & -4 & -3 \ 2 & -6 & -5]\end{array}}

{\left[\begin{array}{ccc}1 & 4 & -1 \ 4 & -5 & -1 \ 1 & -5 & -7]\end{array}}

AP EAPCET 21 May 2025 Shift 2 Paper

Section: Mathematics

Question : 4 of 160

Marks: +1, -0

If A=[

], then A+2A−1=

[AP EAPCET 21 May 2025 S2]

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