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Question : 59 of 160
Marks:
+1,
-0
Solution:
‌| √2−√1+cos‌x |
| √15+cos‌2‌x−4 |
By rationalizing
Nr and
Dr, we get
‌‌| 2−1−cos‌x |
| √2+√1+cos‌x |
×‌| √15+cos‌2‌x+4 |
| 15+cos‌2‌x−16 |
‌=‌| 1−cos‌x |
| −(1−cos‌2‌x) |
×‌‌=−‌‌Using result
‌=‌=−‌×‌×‌=−‌
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