Suppose the axes are to be rotated through an angle \theta so as to remove the x y form from the equation 3 x^2+2 \sqrt{3} x y+y^2=0. Then in the new coordinate system the equation [AP EAPCET 21 May 2024 Shift 2]

Correct Answer is : (2+√3)x2+(2−√3)y2+2xy=4

(2+\sqrt{3}) x^2+(2-\sqrt{3}) y^2+2 x y=4

(2-\sqrt{3}) x^2+(2+\sqrt{3}) y^2-2 x y=4

x^2+y^2-2(2-\sqrt{3}) x y=4(2-\sqrt{3})

x^2+y^2+2(2+\sqrt{3}) x y=4(2+\sqrt{3})

AP EAPCET 21 May 2024 Shift 2 Solved Paper

Section: Mathematics

Question : 42 of 160

Marks: +1, -0

Suppose the axes are to be rotated through an angle θ so as to remove the xy form from the equation 3x2+2√3xy+y2=0. Then in the new coordinate system the equation

[AP EAPCET 21 May 2024 Shift 2]

(2+√3)x2+(2−√3)y2+2xy=4
(2−√3)x2+(2+√3)y2−2xy=4
x2+y2−2(2−√3)xy=4(2−√3)
x2+y2+2(2+√3)xy=4(2+√3)

Validate

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