In a Carnot engine, when the temperatures are T_2=0^{\circ} {\C} and T_1=200^{\circ} {\C}, its efficiency is \eta_1 and when the temperatures are T_1=0^{\circ} {\C} and T_2=-200^{\circ} {\C}, its efficiency is \eta_2. Then the value of \frac{\eta_1}{\eta_2} is [AP EAPCET 21 May 2024 Shift 1]

AP EAPCET 21 May 2024 Shift 1 Solved Paper

Section: Physics

Question : 98 of 160

Marks: +1, -0

In a Carnot engine, when the temperatures are T2=0∘C and T1=200∘C, its efficiency is η1 and when the temperatures are T1=0∘C and T2=−200∘C, its efficiency is η2. Then the value of ‌

η1

η2

[AP EAPCET 21 May 2024 Shift 1]

0.58
0.73
0.64
0.42

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