If z=x+i y, x^2+y^2=1 and z_1=z e^{i \theta}, then {z_1^{2 n}-1}/{z_1^{2 n}+1}= [AP EAPCET 20 May 2024 Shift 2]

Correct Answer is : −itan(n(θ+Tan−1(yx)))

-i \tan (n (\theta+{\Tan}^{-1} (\frac{y}{x}) ) )

i {\Cot} (n (\theta+{\Tan}^{-1} \frac{y}{x}) )

i \tan (n (\theta+{\Tan}^{-1} \frac{x}{y}) )

i \tan (n (\theta+{\Tan}^{-1} \frac{y}{x}) )

AP EAPCET 20 May 2024 Shift 2 Solved Paper

Section: Mathematics

Question : 9 of 161

Marks: +1, -0

If z=x+iy,x2+y2=1 and z1=zeiθ, then ‌

z12n−1

z12n+1

[AP EAPCET 20 May 2024 Shift 2]

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