\left|\begin{array}{ccc}a & b & c \ a^2 & b^2 & c^2 \ 1 & 1 & 1|\end{array} is not equal to [AP EAPCET 20 May 2024 Shift 2]

Correct Answer is : |a+bb+cc+aa2+b2b2+c2c2+a2222|

\left|\begin{array}{ccc}a+1 & b+1 & c+1 \ a^2+1 & b^2+1 & c^2+1 \ 1 & 1 & 1|\end{array}

\left|\begin{array}{ccc}a-b & b-c & c \ a^2-b^2 & b^2-c^2 & c^2 \ 0 & 0 & 1|\end{array}

\left|\begin{array}{ccc}a(a+1) & b(b+1) & c(c+1) \ a+1 & b+1 & c+1 \ -1 & -1 & -1|\end{array}

\left|\begin{array}{ccc}a+b & b+c & c+a \ a^2+b^2 & b^2+c^2 & c^2+a^2 \ 2 & 2 & 2|\end{array}

AP EAPCET 20 May 2024 Shift 2 Solved Paper

Section: Mathematics

Question : 4 of 161

Marks: +1, -0

| is not equal to

[AP EAPCET 20 May 2024 Shift 2]

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