If the circles x^2+y^2-8 x-8 y+28=0 and x^2+y^2-8 x-6 y+25-\alpha^2=0 have only one common tangent, then \alpha= [AP EAPCET 20 May 2024 Shift 1]

AP EAPCET 20 May 2024 Shift 1 Solved Paper

Section: Mathematics

Question : 50 of 160

Marks: +1, -0

If the circles x2+y2−8x−8y+28=0 and x2+y2−8x−6y+25−α2=0 have only one common tangent, then α=

[AP EAPCET 20 May 2024 Shift 1]

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