AP EAPCET 20 May 2024 Shift 1 Solved Paper

Section: Mathematics
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Question : 28 of 160
 
Marks: +1, -0
Match the items of List-I with those of List-II (Here denotes the area of ABC.)
 List I  List II
 A) cotA  I) (a+b+c)2
1
4
 B) cot
A
2
 II) (a2+b2+c2)
1
4
 C) If tanA:tanB:tanC=1:2:3, then sinA:sinB:sinC=  III) 8:6:5
 D)If cot
A
2
:cot
B
2
:cot
C
2
=3
:7
:9
, then a:b:c=
 IV) 12:5:13
   V) 5:22:3
   (VI) 4Δ
Then the correct match is
[AP EAPCET 20 May 2024 Shift 1]
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