\\int{\sec x}/{\\sqrt{\sin (2 x+\\theta)+\sin \\theta} d x=

Correct Answer is : √2(tanx+tanθ)secθ+c

\\sqrt{(\tan x+\tan \\theta) \sec \\theta}+c

\\sqrt{2(\tan x+\tan \\theta) \sec \\theta}+c

\\sqrt{2(\sin x+\tan \\theta) \sec \\theta}+c

\\sqrt{2(\cos x+\tan \\theta) \sec \\theta}+c

AP EAPCET 20-Aug-2021 Shift 2 Paper

Section: Mathematics

Question : 77 of 160

Marks: +1, -0

∫

sec‌x

√sin(2x+θ)+sin‌θ

dx=

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