AP EAPCET 20-Aug-2021 Shift 2 Paper

ax2+2hxy+by2=0 represent a homogeneous line.
Let the two lines by y=m1x,y=m2x
The line y=m1x passes through (2,3) is
3=m1×2 ⇒m1=

3

2

Thus, the equation of line is 3x−2y=0
Similarly, equation of the second line which passes through (4,5) is 5x−4y=0
Thus, the equation of pair of lines is(5x−4y)(3x−2y)=0
15x2−22xy+8y2=0
Compare it with the given equation
a=15,h=−11,b=8
Hence, a+2h+8=15−22+8=1