Given \overrightarrow{a}=3 \stackrel{\^}{i}-\stackrel{\^}{j}, \overrightarrow{b}=2 \stackrel{\^}{i}+\stackrel{\^}{j}-3 \stackrel{\^}{k} and \overrightarrow{b}={b_{1}}^{\to}+{b_{2}}^{\to} where {b_{1}}^{\to} is parallel to \overrightarrow{a} and {b}_\overrightarrow{2}is perpendicular to \overrightarrow{a} then {b_{2}}^{\to} is equal to

Correct Answer is : 12^i+32^j−3^k

\frac{1}{2} \stackrel{\^}{i}+\frac{3}{2} \stackrel{\^}{j}-3 \stackrel{\^}{k}

\frac{1}{2} \stackrel{\^}{i}-\frac{3}{2} \stackrel{\^}{j}+3 \stackrel{\^}{k}

\frac{1}{2} \stackrel{\^}{i}+\frac{3}{2} \stackrel{\^}{j}+3 \stackrel{\^}{k}

\frac{1}{2} \stackrel{\^}{i}-\frac{3}{2} \stackrel{\^}{j}-3 \stackrel{\^}{k}

AP EAPCET 20-Aug-2021 Shift 2 Paper

Section: Mathematics

Question : 35 of 160

Marks: +1, -0

Given

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−

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−3

and

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where

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is parallel to

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and

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is perpendicular to

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then

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is equal to

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