Let \overrightarrow{a}=\stackrel{\^}{i}-\stackrel{\^}{j}, \overrightarrow{b}=\stackrel{\^}{j}-{k^{\^}} and {c^{\to}}=\stackrel{\^}{k}-\stackrel{\^}{i}. If \overrightarrow{d} is a unit vector such \overrightarrow{a} \.\overrightarrow{b}=0=[{b} ^{\to}\overrightarrow{c} \overrightarrow{d}] then \overrightarrow{d} is

Correct Answer is : ±^i+^j−2^k√6

\\pm\stackrel{\^}{{i}+\stackrel{\^}{j}-{k^{\^}}}/{\\sqrt{3}

\\pm\stackrel{\^}{{i}+\stackrel{\^}{j}-{2k^{\^}}}/{\\sqrt{6}

\\pm\stackrel{\^}{{i}+\stackrel{\^}{j}+{k^{\^}}}/{\\sqrt{3}

\\pm\stackrel{\^}{{i}+\stackrel{\^}{j}+{2k^{\^}}}/{\\sqrt{6}

AP EAPCET 20-Aug-2021 Shift 2 Paper

Section: Mathematics

Question : 32 of 160

Marks: +1, -0

Let

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and

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. If

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is a unit vector such

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=0=[

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] then

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