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Question : 30 of 160
Marks:
+1,
-0
Solution:
(a) Points
(+2),(2−) i.e.
(1,2) and
(2,−1) .
Line joining points
(1,2) and
(2,−1) is
y−2=(x−1) or
y−2=−3x+3 y+3x=5 ...(i)
Points
(−),(2) i.e.
(−1,0),(2,0) Line joining points
(−1,0),(2,0) is
y−0=(x+1) ⇒y=0 ...(ii)
Solve Eqs. (i) and (ii) for
x and
y, we get
y=0,x= ∴ Point of intersection
(,0).
i.e.
+0=
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