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Question : 28 of 160
Marks:
+1,
-0
Solution:
=++,
=−+2 and
=x+(x−2)− Given,
c lies in the plane of
a and
b Then,
[a,b,c]=0 ⇒[a,b,c]=[]=0 1(1−2(x−4−1(−1−2x) +1(x−2+x)=0 ⇒1−2x+4+1+2x+x−2+x=0 ⇒2x+4=0 ⇒x=−2
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