AP EAPCET 20-Aug-2021 Shift 2 Paper

Given, initial and final temperatures be T1 and T2 i.e. 27°C and 127°C .
∴T1=27+273=300K and T2=127+273=400K
Let, initial and final rms velocities be v1 and v2.
Since, rms speed, vrms=√

3‌RT

M

where, R is universal gas constant and M is molar mass.
∴vrms∝√T
⇒

V1

V2

=√

T1

T2

=√

300

400

=

√3

2

∴

Δv

v

×100=

v2−v1

v1

×100
=(

v2

v1

−1)×100 =(

2

√3

−1)×100=15.5%