AP EAPCET 20-Aug-2021 Shift 1 Paper

Given, range of projectile, R=100m
Let initial and final velocities be u and v and angle of projection be θ.
As we know that,
In case of projectile motion, the final velocity of body always less than that of initial velocity of projection (v<u) and kinetic energy (KE)=

1

2

mv2
where, m is mass and v is velocity.
∴ Kinetic energy will be again maximum, when is will be again on ground at 100m from point of projection.