The equation of a straight line which passes through the point (\a \cos ^{3} \\theta, \a \sin ^{3} \\theta) and perpendicular to (x \sec \\theta+y \cosec\\theta)=a is

Correct Answer is : xcosθ−ysinθ=acos2θ

\frac{x}{a}+\frac{y}{b}=a \cos \\theta

x \cos \\theta-y \sin \\theta=a \cos 2 \\theta

x \cos \\theta+y \sin \\theta=a \cos 2 \\theta

x \cos \\theta+y \sin \\theta-a \cos 2 \\theta=1

AP EAPCET 20-Aug-2021 Shift 1 Paper

Section: Mathematics

Question : 46 of 160

Marks: +1, -0

The equation of a straight line which passes through the point (acos3θ,asin3θ) and perpendicular to (x‌sec‌θ+y‌cosec‌θ)=a is

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