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Question : 32 of 160
Marks:
+1,
-0
Solution:
Line passing through
(1,1,−1) and parallel to
(1,2,−1) is
L1:===λ L2:===µ For
A:(λ+1,2λ+1,−λ−1) =(−µ+3,5µ−2,−4µ+2) ⇒λ+µ=2⇒2λ+1=5µ−2 ⇒4−2µ+1=5µ−2 1=µ and
λ=1 A:(2,3,−2) P:2x−y+2z+7=0 ⇒2(λ+1)−(2λ+1)+(−2λ−2)+7=0 ⇒−2λ+6=0⇒λ=3 B:(4,7,−4) AB2=22+42+22=24 AB=2√6
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