AP EAPCET 20-Aug-2021 Shift 1 Paper

According to given diagram, As we know that, F=

µ0

2π

.

I1I2

d

l
where, F is force, µ0 is 4π×10−7,I1 and I2 are currents in conductors, l is length of conductor and d is separation between two wires. As same sense of current, attract whereas opposite sense, repel.
∴ Net force, Fnet=(

µ0

2π

I1I2

d1

−

µ0

2π

I1−I2

d2

)l
=

µ0

2π

.(

2×1

2×10−2

−

2×1

12×10−2

)15×10−2 =25×10−7N, towards wire