If {\A}=\left[\begin{array}{cccc}2 & 1 & 3 & -1 \ 1 & -2 & 2 & -3]\end{array}, {\B}=\left[\begin{array}{cccc}2 & 1 & 0 & 3 \ 1 & -1 & 2 & 3]\end{array} and 2 {\A}+3 {\B}-5 {\C}=0, then {\C}=

Correct Answer is : [216∕57∕51−7∕523∕5]

\left[\begin{array}{cccc}2 & 1 & 6 \/ 5 & 7 \/ 5 \ 1 & 7 \/ 5 & 2 & 3 \/ 5]\end{array}

[\table -2 , 1 , 6 \/ 5 , 7 \/ 5 ; 1,-7 \/ 5 , 2 , 3 \/ 5]

\left[\begin{array}{cccc}-2 & 1 & 6 \/ 5 & 7 \/ 5 \ 1 & 7 \/ 5 & 2 & 3 \/ 5]\end{array}

\left[\begin{array}{cccc}2 & 1 & 6 \/ 5 & 7 \/ 5 \ 1 & -7 \/ 5 & 2 & 3 \/ 5]\end{array}

AP EAPCET 19th May 2023 Shift 1 Solved Paper

Section: Mathematics

Question : 4 of 160

Marks: +1, -0

If A=[

2	1	3	−1
1	−2	2	−3

],B=[

2	1	0	3
1	−1	2	3

] and 2A+3B−5C=0, then C=

Go to Question:

Prev Question

Next Question

2	1	6∕5	7∕5
1	7∕5	2	3∕5

−2	1	6∕5	7∕5
1	−7∕5	2	3∕5

−2	1	6∕5	7∕5
1	7∕5	2	3∕5

2	1	6∕5	7∕5
1	−7∕5	2	3∕5