AP EAPCET 19 May 2024 Shift 2 Solved Paper
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If the circle S = 0 x 2 + y 2 − 2 x + 6 y = 0 , x 2 + y 2 − 4 x − 2 y + 6 = 0 x 2 + y 2 − 12 x + 2 y + 3 = 0 ( 0 , 3 ) S = 0
[AP EAPCET 19 May 2024 Shift 2]
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