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Question : 75 of 160
Marks:
+1,
-0
Solution:
Let‌I=∫dx =log‌cot‌.∫cos‌x‌d‌x −∫[(log‌cot‌)‌∫cos‌x‌d‌x]dx ‌‌‌‌‌‌‌‌ [integrating by parts]
=log(cot‌).sin‌x−∫−cosec2..sin‌x‌d‌x =(sin‌x)‌log‌cot‌+∫1dx =(sin‌x)‌log‌cot‌+x+c
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