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Question : 60 of 160
Marks:
+1,
-0
Solution:
AB =
a =
B - A
=(5−6)−(−+2−3) =6−2−3 AC =
c =
C -
A =(4−)−(−+2−3) =+2+2 Internal angle bisector
=+ =+ =+ =++ =++ DR's of internal bisector of
∠BAC=,, Direction Cosines
=,
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