AP EAPCET 19-Aug-2021 Shift 2 Paper

Let P(x,y) be any point on the circle, therefore it will satisify the circle
(x1−3)2+(y1+2)2=5r2 ...(i)
The length of tangent drawn from point P(x1,y1) to the circle (x−3)2+(y+2)2=r2 is
√(x1−3)2+(y1+2)2−r2=√5r2−r2 [from Eq. (i)]
=√4r2=2r
According to the question,
16=2r
⇒ r = 8
∴ Area between two circles =5πr2−πr2
=4πr2=4π.82
=256π sq units